Question

A bag contains a red ball, a blue ball and an yellow ball, all the balls being of the same size. Manasa takes out a ball from the bag without looking into it. What is the probability that she takes a (i) yellow ball? (ii) red ball? (iii) blue ball?

Answer 1

Probability of yellow ball 1/3,probability of red ball 1/3 probability of blue ball 1/3

Answer 2

Answer:

$Total \: number \:balls \: in \:the \:bag = 3$

$Total \: number \:of \: outcomes = 3$

$\boxed { \pink { Probability = \frac{ No. \:of \: favourable \: outcomes }{Total \: number \:of \: outcomes }}}$

/* If Manasa takes out a ball from the bag without looking into it ,then

$i) P(yellow \:ball) = \frac{1}{3}$

$ii) P(red \:ball) = \frac{1}{3}$

$i) P(blue \:ball) = \frac{1}{3}$

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