A bag contains cands numbred from 2 to 26 one card is drawn the bag at random find the probability that it has a number divisible by both 2 and 3
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26-2+1=25
lcmof 2 and 3=6
25/6= approx 1/4
brainliest plz??
lcmof 2 and 3=6
25/6= approx 1/4
brainliest plz??
Answered by
5
the probability of getting numbers divisible by both 2 and 3 are:
6, 12, 18, 24 (4 numbers)
Since only one card can be drawn which is divisible by both 2 and 3. therefore, it will be 1/4
6, 12, 18, 24 (4 numbers)
Since only one card can be drawn which is divisible by both 2 and 3. therefore, it will be 1/4
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