A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. Find the
probability that the number on this card is (i) divisible by both 2 and 3 (ii) a two digit number
Answers
Answered by
6
Answer:
(i) 4 / 25
(ii) 16 / 25
Hope this helps.
Step-by-step explanation:
(i) P(divisible by both 2 and 3)
= P(divisible by 6)
= (# ways getting a number divisible by 6) / (# ways of choosing a card)
= (# of numbers in {6, 12, 18, 24} ) / 25
= 4 / 25
(ii) P(two digit number)
= (# two digit numbers up to 25) / 25
= (25 - 9)/25
= 16 / 25
Answered by
2
Answer:
Step-by-step explanation:
Total = 25
1) ----------------
OBSERVATION = 2,3,4,6,8,9,10,12,15,16,18,20,21,22,24
=15
Therefore
P(E) = 15/25 = 3/5................
2) ---------------
Observation = 25-9 = 16
Therefore
P(E) = 16/25...............
Hope you understood
Hope helpful mate ❤❤❤
Mark as brainlist answer
Tnx
CRAZYMIND:
Mark as brainlist answer
Tnx
The question asked for the probability that the number is divisible by BOTH 2 AND 3. The probability calculated here is that the number is divisible by EITHER 2 OR 3.!!! The answer in the other solution is correct.
Bro see written that divisible by both 2 and 3
And I have written the observations also
That's right.... "both 2 and 3". And yes, look at the listed observations. Numbers like "4" are NOT divisible by "both 2 and 3". The solution below lists the correct observations that satisfy "is divisible by both 2 and 3". They are: 6, 12, 18, 24.
Bro I send you a request accept it
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