Question

A bag contains coins of denomination of 50 paise and five rupees. The total value of these
coins is Rs 300. If the total number of coins in the bag is 150, find the number of coins of
each denomination.​

Answer 1

Answer:

Let 50 paise coins be x

5 rupees coins will be (150-x) as there are 50 coins in the bag

50 paise = 100/50=1/2 rupees

1/2(x) + 5(150-x) = 300 rupees

x/2+750-5x = 300 rs

-9x/2+750= 300

750-300 = 9x/2

450= 9x/2 => 9x = 900 => x=900/9 = 100 (50-paise coins )

5 rupees coins = 150-x = 150-100 = 50 coins

Answer 2

Answer:

Step-by-step explanation:

let 50 paise coins be x

5 rupees coins will be (150-x) as there are q50 coins in the bag

50 paise = 100/50=1/2 rupees

1/2(x)+5(150-x)= 300 rupees

x/2+750-5x = 300 rs

-9x/2+750= 300

750-300 = 9x/2

450= 9x/2 => 9x = 900 => x=900/9 = 100 (50-paise coins )

5rupees coins => 150-x => 150-100=> 50 coins