A bag contains coins of denomination of 50 paise and five rupees. The total value of these
coins is Rs 300. If the total number of coins in the bag is 150, find the number of coins of
each denomination.
Answers
Answered by
2
Answer:
Let 50 paise coins be x
5 rupees coins will be (150-x) as there are 50 coins in the bag
50 paise = 100/50=1/2 rupees
1/2(x) + 5(150-x) = 300 rupees
x/2+750-5x = 300 rs
-9x/2+750= 300
750-300 = 9x/2
450= 9x/2 => 9x = 900 => x=900/9 = 100 (50-paise coins )
5 rupees coins = 150-x = 150-100 = 50 coins
Answered by
2
Answer:
Step-by-step explanation:
let 50 paise coins be x
5 rupees coins will be (150-x) as there are q50 coins in the bag
50 paise = 100/50=1/2 rupees
1/2(x)+5(150-x)= 300 rupees
x/2+750-5x = 300 rs
-9x/2+750= 300
750-300 = 9x/2
450= 9x/2 => 9x = 900 => x=900/9 = 100 (50-paise coins )
5rupees coins => 150-x => 150-100=> 50 coins
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