Question

a bag contains coins of denomination of rs5 and rs 2.the total value of these coins is rs 1272.if the number of two ruppes coins is 15% of the five rupee coins, find the number of coins of each denomimation.

Answer 1

Please see the attachment

Answer 2

Given:

A bag contains coins of denominations of Rs.5 and Rs.2. The total value of these coins is Rs. 1272. Also, the number of two rupees coins is 15% of the five rupee coins.

To find:

The number of coins of each denomination.

Solution:

The number of Rs. 5 coins is 240 and the number of Rs. 2 coins is 36.

Let the number of coins of Rs. 5 be x.

So, according to the question,

The number of coins of Rs. 2

$= \frac{15}{100} x$

$= \frac{3}{20} x$

Now,

The total value of coins = Rs. 1272

So,

$5(x )+ 2( \frac{3}{20} x) = 1272$

This can be written as

$5x + \frac{3}{10} x= 1272$

Now, on taking 10 as LCM, we have

$\frac{50x + 3x}{10} = 1272$

$53x = 12720$

$x = 240$

So,

The number of coins of Rs. 2

$= \frac{3}{20} (240)$

$= 3 \times 12$

$= 36$

Hence, the number of Rs. 5 and Rs. 2 coins is 240 and 36 respectively.