Question

A bag contains five white and four red balls. two balls are picked at random from the bag. what is the probability that they both are different color?

Answer 1

The probability will be for
white ball - 5/9
red ball - 4/9

the answer can be 5/9 and 4/9 or 1
I hope this answer is true

Answer 2

Answer:  The required probability is 55.56%.

Step-by-step explanation:  Given that a bag contains five white and four red balls. two balls are picked at random from the bag.

We are to find the probability that both the balls are of different colors.

According to the given information, one ball is white in color and the other ball is red in color.

Let S denotes the sample space for the experiment of choosing two balls at random from 5 white and 4 red balls.

And, let A denote the event that one ball is white and the other is red.

Then,

$n(S)=^9C_2=\dfrac{9!}{2!(9-2)!}=\dfrac{9\times8\times7!}{2\times1\times7!}=36,\\\\\\n(A)=^5C_1\times^4C_1=\dfrac{5!}{1!(5-4)!}\times\dfrac{4!}{1!(5-1)!}=5\times4=20.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{20}{36}=\dfrac{5}{9}\times100\%=55.56\%.$

Thus, the required probability is 55.56%.