A bag contains in 50 balls. Some of them are white , some are blue and some are red. The number of White balls is 11 times than the number of blue balls. The number of red balls is less than the number of white balls . Also the number of red balls is more than the number of blue balls. If one of the balls is a selected at random. What is the probability that it is red?
Answers
Answer:
Probability of read is 14 / 50 = 0.28
Step-by-step explanation:
Let the numbers of blue, white and red balls be b, w and r, respectively.
Then b + w + r = 50 and b < r < w and w = 11b.
From b + w + r = 50 and w = 11b, we get
12b + r = 50.
So there are only 5 possible values for b: 0, 1, 2, 3 and 4.
Check them one at a time:
b = 0 => r = 50 and w = 0, but we need r < w, so this is not correct.
b = 1 => r = 50 - 12 = 38 and w = 11, but we need r < w, so this is not correct.
b = 2 => r = 50 - 24 = 26 and w = 22, but we need r < w, so this is not correct.
b = 3 => r = 50 - 36 = 14 and w = 33. This satisfies b < r < w, so could be the answer.
b = 4 => r = 50 - 48 = 2, but we need b < r, so this is not correct.
The only possibility is b = 3, r = 14, w = 33.
The probability of getting red is then 14 / 50 = 0.28