At present Asha's age is 2 more than the square of a Daughter Nisha's age. When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times the present age of Nisha. Find the present ages of both Asha and Nisha.
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Answered by
2
Answer:
Step-by-step explanation:
Let Ashas age be x
Nishas age be y
x=2+y²
2+y²=1-10 (2+y²)
2+y²=1-20-10y²
2+19=-11y²
21/11=y²
∴y=2
x=2+2²
x=2+4
∴x=6
Answered by
4
Let Nisha’s age be x. Then Asha’s age will be x^2+2
When Nisha reaches x^2+2, Ashas age would be (x^2+2)+(x^2+2-x)=2x^2-x+4
2x^2-x+4=10x-1
2x^2-11x+5=0
(2x-1)(x-5)=0
So x is either 5 or 1/2
So present age of Asha’s age is 27 and Nisha’s age is 5
When Nisha reaches x^2+2, Ashas age would be (x^2+2)+(x^2+2-x)=2x^2-x+4
2x^2-x+4=10x-1
2x^2-11x+5=0
(2x-1)(x-5)=0
So x is either 5 or 1/2
So present age of Asha’s age is 27 and Nisha’s age is 5
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