Math, asked by Deepak109473, 1 year ago

At present Asha's age is 2 more than the square of a Daughter Nisha's age. When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times the present age of Nisha. Find the present ages of both Asha and Nisha.​

Answers

Answered by aniboss2016
2

Answer:


Step-by-step explanation:

Let Ashas age be x

Nishas age be y

x=2+y²

2+y²=1-10 (2+y²)

2+y²=1-20-10y²

2+19=-11y²

21/11=y²

∴y=2

x=2+2²

x=2+4

∴x=6

Answered by shameemamk
4
Let Nisha’s age be x. Then Asha’s age will be x^2+2

When Nisha reaches x^2+2, Ashas age would be (x^2+2)+(x^2+2-x)=2x^2-x+4

2x^2-x+4=10x-1
2x^2-11x+5=0

(2x-1)(x-5)=0

So x is either 5 or 1/2

So present age of Asha’s age is 27 and Nisha’s age is 5
Similar questions