A bag contains one rupee 50-paise and 25-paise coins in the ratio 5:6:7. If the total amountvis rs 390 find the number of coins of each kind
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Let the no. of Rs 1, 50 paise and 25 paise coins be 5x, 6x and 7x respectively.
- Value of Rs 1= Rs(1×5x)= Rs5x
- Value of Rs 1/2= Rs(1/2×6x)= Rs3x
- Value of Rs 1/4=Rs(1/4×7x)=Rs 7x/4
ATQ,
5x+3x+7x/4= 390
20x+12x+7x/4=390
39x/4= 390
x=390×4/39
x= 40
Therefore, no. of 1rupee coins=200
no. of 50 paise coins=240
no. of 25 paise coins=280
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