A bag contains one rupee, fifty paise and 25 paise coins in ratio 1 is to 2 is to 3 respectively. If total value of the coin is Rs 330 find the total number of coins and also find the number of coins in each denomination.
Answers
AnswEr :
- Rs. 1 : 50 paise : 25 paise = 1 : 2 : 3
- Total Value of Coins = Rs. 330
Either convert all Terms in Paise or Rupees, I'm converting all terms in Paise.
Let Number of Coins be n, 2n & 3n.
• According to the Question Now :
↠ Total value of coins = Rs. 330
↠ (No. × Value) of each terms = Rs. 330
↠ (Rs. 1 × n) + (50 paise × 2n) + (25 paise × 3n) = Rs. 330
- Converting all terms into paise
↠ (100 × n) + 100n + 75n = 330 × 100
↠ 100n + 100n + 75n = 33,000
↠ 275n = 33,000
- Dividing both term by 275
↠ n = 120
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• D E N O M I N A T I O N S :
◗ Rs. 1 = n = 120 Coins
◗ 50 paise = 2n = 2(120) = 240 Coins
◗ 25 paise = 3n = 3(120) = 360 Coins
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• VALUE OF EACH DENOMINATIONS :
◗ Rs. 1 = n × 1 = 120 × 1 = Rs. 120
◗ 50 paise = 2n × 1/2 = n = Rs. 120
◗ 25 paise = 3n × 1/4 = 360 × 1/4 = Rs. 90
∴ Number of Rs. 1, 50 paise & 25 paise will be 120, 240 & 360 with value of Rs. 120, Rs. 120 & Rs. 90 respectively.
A bag contains one rupee, fifty paise and 25 paise coins in ratio 1:2:3 respectively. If total value of the coin is 330.
The total number of coins & also the number of coins in each denomination.
Let the ratio be R.
So,
- R
- 2R
- 3R
A/q
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Total number of coins is 120.
- 1 Rupee = 120.
- 50 paisa = 2(120) = 240.
- 25 paisa = 3(120) = 360.