two cubes each of volumes 513cm cube are joined end to end. find the surface area of the resultant cuboid
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hey mate ...
here is your answer...
volume=513
![a {}^{3} = 513 a {}^{3} = 513](https://tex.z-dn.net/?f=a+%7B%7D%5E%7B3%7D++%3D+513)
![a = 8.005 a = 8.005](https://tex.z-dn.net/?f=a+%3D+8.005)
in the cuboid formed,
![l = 16.010 \\ b = 8.005 \\ h = 8.005 l = 16.010 \\ b = 8.005 \\ h = 8.005](https://tex.z-dn.net/?f=l+%3D+16.010+%5C%5C+b+%3D+8.005+%5C%5C+h+%3D+8.005)
surface area of cuboid =
![2(lb + bh + lh) 2(lb + bh + lh)](https://tex.z-dn.net/?f=2%28lb+%2B+bh+%2B+lh%29)
![= 448.560 = 448.560](https://tex.z-dn.net/?f=+%3D+448.560)
hope it helps you..
PPP lease mark as brainliest
here is your answer...
volume=513
in the cuboid formed,
surface area of cuboid =
hope it helps you..
PPP lease mark as brainliest
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