Question

a bag contains red and black balls if 5 black balls are added and 7 red ballsballs are removed from the bag the number of red balls and black balls will be equal if 3 red balls are removed the number of red balls will be 1 more than double the number of black balls how many balls of each type are there​

Answer 1

Step-by-step explanation:

Let the number of red balls be X and black balls be Y

Y+5 = X-7

X = Y+12

X-3 = 2Y+1

X = 2Y+4

Therefor,

Y+12 = 2Y+4

12-4 = 2Y-Y

8 = Y

X = 2Y+4

= 2×8 +4

= 16+4

= 20

Therefor Number of red balls is equal to 20 and number of black balls is equal to 8