Question

help me for solution..........​

Answer 1

$\large{\huge{\underline \mathbb{ \overline { \mid{ \blue{Question : - } \mid}}}} } \\ x - y = 4 \: and \: xy = 45 \\To \: find = x {}^{3} - {y}^{3} \\ \\ \large{\huge{\underline \mathbb{ \overline { \mid{ \red{Answer : - } \mid}}}} } \\ \\ (x - y) {}^{3} = {x}^{3} - {y}^{3} - 3 {x}^{2} y + 3xy {}^{2} \\ \\ 4 {}^{3} = {x}^{3} - {y}^{3} - 3xy(x - y) \\ \\ 64 = x {}^{3} - {y}^{3} - 3(45)(4) \\ \\ 64 = {x}^{3} - {y}^{3} - 540 \\ \\ \large\boxed{ \purple{ 604 = {x}^{3} - {y}^{3}} }\\ \\ \blue{ so \: the \: value \: of \: x {}^{3} - {y}^{3 \: } comes} \\ \blue{ out \: to \: be \: 604.} \\ \\ \boxed{ \large \pink{Formula \: applied : - }} \\ \\ (x - y) {}^{3} = x {}^{3} - {y}^{3} - 3x {}^{2} y + 3xy {}^{2}$

Answer 2

Answer:

${(x - y)}^{3} = {x}^{3} - {y}^{3} - 3 {x}^{2}y \: + 3x {y}^{2}$

${x}^{3} - {y}^{3} = {(x - y)}^{3} + 3 {x}^{2}y \: - 3x {y}^{2}$

$x - y = 4 \: and \: \\ xy = 45 \: \: (given)$

$substituting \: all \: the \: values$

$= {4}^{3} + 3( {x}^{2}y - x {y}^{2})$

$= 64 + 3(45x - 45y)$

$= 64 + 135(4) \\ = 64 + 540 \\ = 604$

$hope \: it \: helps \: you \\ \\ mark \: me \: as \: brainliest....$