Question

A bag contains Red, Green and Yellow balls. A ball is taken at random from the bag. The probability that it is Red is 0.35 and the probability that it is Green is 0.4 Find the probability that ball selected is: Yellow Not Red

Answer 1

Answer:

(I) p(red)+p(yellow)+p(green)=1. (because sum of all probabilities is 1)

0.35+p(yellow)+0.4=1

0.39+p(yellow)=1

p(yellow)=1-0.39

p(yellow)=0.61

(2) p(red)+p(not red) =1. (because sum of all probabilities is 1)

0.35+p(not red) =1

p(not red) =1-0.35

p(not red) =0.65

Answer 2

Answer:

12 red,9 green,8 blue,5 yellow

12 red,9 green,8 blue,5 yellowTotal balls=34

12 red,9 green,8 blue,5 yellowTotal balls=34i) probability of green ball=9/34

12 red,9 green,8 blue,5 yellowTotal balls=34i) probability of green ball=9/34ii)probability of yellow ball=5/34

12 red,9 green,8 blue,5 yellowTotal balls=34i) probability of green ball=9/34ii)probability of yellow ball=5/34iii)probability of white ball=0/34=0

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