A bag contains Rs 155 in the form of 1 rupee, 50 pause and 10 pause in the ratio 3:5:7. Find the number of each type of coins.
Answers
Answered by
4
so according to the question,
let x be the no of coins
so,
3X+5X+7X=155 (the total no of coins equal to rs.155)
15x=155
x=155/15
x=10.3
so,
3X= 3*10.3=31(approx.)
5X=5*10.3=52(approx.)
7X=7*10.3=72(approx.)
THEREFORE THE BAG CONTAINS
THIRTY ONE(31) 1 RUPEES
FIFTY TWO(52) 50 PAISE
SEVENTY TWO(72) 10PASIE
and there after
31+52+72=155
let x be the no of coins
so,
3X+5X+7X=155 (the total no of coins equal to rs.155)
15x=155
x=155/15
x=10.3
so,
3X= 3*10.3=31(approx.)
5X=5*10.3=52(approx.)
7X=7*10.3=72(approx.)
THEREFORE THE BAG CONTAINS
THIRTY ONE(31) 1 RUPEES
FIFTY TWO(52) 50 PAISE
SEVENTY TWO(72) 10PASIE
and there after
31+52+72=155
TUshukla:
YOU HAVE TAKEN X COINS OF EACH TYPE WHICH WOULD NOT BE RIGHT
IT IS BCOZ THE VALUE OF COINS DIFFERS
yes.. i have taken X.. and the values are differing
BUT IT IS NOT RIGHT AS THERE WOULD BE 25 COINS OF EACH TYPE
but you cannot have points also..
Answered by
0
THERE WERE 25 COINS OF EACH TYPE
AS 3×1×25=75
5×0.5×25=62.5
7×0.1×25=17.5
NOW,ADDING 75+62.5+17.5=155
AS 3×1×25=75
5×0.5×25=62.5
7×0.1×25=17.5
NOW,ADDING 75+62.5+17.5=155
then you cant have points for your answer...
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