Question

A bag contains rs 187 in the form of 1 rupee 5p0aise and 10 paise coins in the ratio 3:4:5. Find the number of each type of coins

Answer 1

Answer:

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Step-by-step explanation:

Let the number of one rupee coins = 3 k —-(1)

Then the number of 50paise coins = 4 k —-(2)

And the number of coins of 10 paise = 5 k —-(3)

The value of 3 k one rupee coins = Rs. 3 k —-(4)

The value of the 4k coins of 50p each = Rs (4k×0.5)= Rs 2 k---(5)

The value of 5k coins each of value 10p = Rs (5 k × 0.1) = Rs 0.5 k —-(6)

Total value in rupees of all the coins = Rs 3 k + Rs 2 k + Rs 0.5 k = Rs 5.5 k

But we know the total value of all the coins = Rs 187

==> 5.5 k = 187; or k = 34

So the number of one Rupee coins = 34 × 3 = 102

The number of coins of value 50 paise each = 34 × 4 = 136

And the number of coins of value 10 paise each = 34 × 5 = 170

The total money value in rupees of all the coins = 102 × 1 + 136 × 0.5 + 170 × 0.1 = 102 + 68 + 17 =187 rupees.