Question

a bag contains Rs 750 in the form of rupee,50 paisa and 25 paisa coins in the ratio 5:8:4 find the number of coins of each type

Answer 1

total amount Rs 750
let there are 5x, 8x and 4x no. of rupee, 50paisa and 25 paisa
according to the question,
5x(1)+8x(0.5)+4x(0.25)=750
5x+4x+x=750
10x=750
x=75
therefore the
no. of coins of rupee = 5*75=375
no. of coins of 50 paisa = 8*75=600
no. of coins of 25 paisa = 4*75=300

hope this helps:p

Answer 2

$<b>Answer:</b>$

105, 126, 672

$<b>Step-by-step explanation:</b>$

Given, Ratio of values = 5 : 6 : 8

                                     = 5 : (6/2) : (8/4)

                                     = 5 : 3 : 2

Given,Total = 210.

Divide 210 in the ratio of 5 : 3 : 2.

(i)

1st part = (210 * 5/10)

            = 105

2nd part = (210 * 3/10)

              = 63.

3rd part = (210 * 8/10)

             = 168

Therefore,

$\textsf{\large{Number of 1-rupee coins = 105.}}$

$\textsf{\large{Number of 50-paise coins = 63 * 2 = 126.}}$

$\textsf{\large{Number of 25-paise coins = 168 * 4 = 672.}}$

Hope it helps!