Question

A bag contains rupee, 50 paise and 25 paise coins in the ratio 5:6:8. if the total amount is rs 420 find the number of coins of each type

Answer 1

Let the no. Of Rs1,50p, and 25p coins be 5x, 6x, 8x.
Total value of coins = Rs( 5x × 1+ 6x × 50/100+8x × 25/100)
= Rs(5x/30 + 3x/30 + 2x/30) {taking l.c.m as 30}
=Rs(10x/30)
But ,the total value of the coin is= Rs 420
Therefore,
10x/30 = 420
=> x= ( 420× 30/10)
=> x= 1260

Number of RS 1 coins = 5x= (5×1260) = 6300
No. Of 50 p coins = 6x=(6×1260) =7560
No of 25 p coins = 8x = (8×1260) = 10080

Answer 2

Answer: Rs.798

Step-by-step explanation:

Let the number of 1rupee, 50p and 25p be 5x,6x and 8x respectively.

:. Total amount of 1rupee =rs 5x

:. Total amount of 50paise=rs (50×6x)/100=rs3x

:. Total amount of 25paise=rs (25×8x)/100=rs2x

:.Total amount =2x+3x+5x

=>420=10x

=> x=420/10

=42

:. no. of 1rupee =5x= 5×42= 210

:. no. of 50p=6x=6×42=252

:. no. of 25p =8x=8×42= 336

:. total number of coins=210+252+336

=798

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TheLostMonkMaths AryaBhatta

ratio of ₹1 , 50p and 25p coins

.

= 5 : 6 : 8

.

let the constant ratio be ' x '

.

₹1 coins = 5x, 50p coins = 6x,

.

25p coins = 8x

.

convert paise to rupees:

-----------------------------------

50p = 50÷100 = ₹ 0.5,

.

25p = 25 ÷ 100 = ₹0.25

.

total amount in the bag = ₹420

.

1( 5x) + 0.5( 6x ) + 0.25( 8x) = 420

.

5x + 3x + 2x = 420

.

10x = 420 => x = 42

.

therefore,

--------------

.

₹1 coins = 5x = 5 × 42 = 210

.

50p coins = 6x= 6 × 42 = 252

.

25p coins = 8x = 8 × 42 = 336

----------------------------

total coins = 210 + 252 + 336 = 798

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total number of coins = 798

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