Question

A bag contains some gold coins and some
silver coins in the ratio 3:2. The cost of gold
coin is 4000% more than that of a silver coin.
If the cost of all the coins in the bag is Rs.
2.2lakhs and the total number of coins in the
bag is 20, find the cost of each gold coin?​

Answer 1

Answer:

18329

Step-by-step explanation:

gold coin is x and silver coin is y

so gold coin is 3x

silver is 2x

total coin in bag is 20

so 3x+2x = 20

5x = 20

x = 4

gold coin in bag is 12

nd cost of gold is 4000% more than silver coin

the cost of total coin is 2.2 lakhs

so let find cost of silver coin

here 8 coins silver

let silver cost price is y

gold coin cost is 4000y of silver coins

8y + 12×4000y = 220000

48008y = 220000

y is 4.58

so cost of gold coin is 18320

Answer 2

Answer:

Cost of 12 gold coins = 203076.92

Cost of 12 gold coins = 203076.92Cost of 8 silver coins = 16923.08

Step-by-step explanation:

Let the no. of 1 silver coin will be 2x.

no. of gold coin = 3x

According to question,

3x + 2x = 20 coins

5x = 20 coins

x = 20/5 coins

x = 4 coins

No. of silver coins = 2×4 = 8 coins

No. of gold coins = 3×4 = 12 coins

Cost of 1 silver coin will be y.

Cost of 8 silver coins = 8y

Cost of 1 gold coin = 4000 % of y + y

= 40y + y

= 41y

Cost of 12 gold coins = 41y × 12

= 492y

According to question,

41y + 492y = 2,20,000

533y = 2,20,000

y = 2,20,000/ 533

Cost of 8 silver coins = 41 × 2,20,000/533

= 2,20,000/13

= 16923.08

Cost of 12 gold coins = 492 × 2,20,000/533

= 12×2,20,000/13

= 2640000/13

= 203076.92

Hope it will help you.

Study well !!!