A bag contains some red and green balls. If we take a ball from it, without looking, the probability of getting a red ball is 1/4. (a) what js the total number of red balls,if there are 8 red balls? (b) what is the probability of that a ball is taken green? (c) find the sum of both the probabilities? I found the answer..but i'm not sure whether it is right or not...help me to find this..plzz
Answers
Answer:
Step-by-step explanation:
Given, (i) bag contains only red and green balls.
(ii) Probability of getting red ball is 1/4.
Method 1:
So answering your questions in reverse order:
c) sum of all probabilities is always 1.,
So sum of both the probabilities = 1.
b) Probability of getting green ball = 1 - probability of getting red ball
= 1 - 1/4 = 3/4.
a) Total red balls = 8
Probability of red ball is 1/4.
Let x be the number of balls (i.e. red + green)
x/4 = 8
=> x = 4*8 = 32.
Method 2:
a) Total red balls = 8
Probability of red ball is 1/4.
Let x be the number of balls (i.e. red + green)
x/4 = 8
=> x = 4*8 = 32.
b) Probability of green balls
Number of green balls = 32 - 8 = 24.
So probability of getting a green ball = 24/32 = 3/4.
c) Sum of all probabilities = 1/4 + 3/4 = 4/4 = 1.