a bag has 4 red balls ,3 yellow and 5 green balls . a ball is drawn from the bag without into it. find the probability of getting
a red balls
b a green ball
c a non yellow ball
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a) 4/(4+3+5)
4/12=1/3
b) 5/(4+3+5)=
5/12
c)(5+4)/(4+3+5) =
9/12= 3/4
4/12=1/3
b) 5/(4+3+5)=
5/12
c)(5+4)/(4+3+5) =
9/12= 3/4
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