Question

A bag has 6 white, 11 red & 7 blue balls. Find out the probability of drawing a white ball out of that bag? ​

Answer 1

REQUIRED ANSWER

Given -

• Number of white balls in bag = 6
• Number of red balls in bag = 11
• Numbers of blue balls in bag = 7

To Find -

• Probability of drawing a white ball out of the bag = ?

Formula -

$\sf \: Probability= \dfrac{ No. \: of \: Favourable \: Outcomes}{Total \: No. \: of \: Outcomes}$

so ,

$\sf \longrightarrow\: Probability= \dfrac{ No. \: of \: white \: balls}{total \: No. \: of \: balls}$

• Number of white balls = 6
• Total number of balls = 6 + 11 + 7 = 24

$\sf \longrightarrow\: Probability= \dfrac{ 6}{24}$

$\sf \longrightarrow\: Probability= \dfrac{ 1}{4}$

Answer 2

Step-by-step explanation:

Given

$\begin{gathered}\bold{Total \ no: \ of \ white \ balls} = 4\\\bold{Total \ no: \ of \ red \ balls} = 6\\\bold{Total \ no: \ of \ black \ balls} = 7\\\bold{Total \ no: \ of \ blue \ balls} = 3\\\implies \bold{Total \ no: \ of \ balls} = 4 + 6 + 7 + 3 =\underline{\underline{20}}\end{gathered} </p><p>$

$(i) \bold{ Probability \ of \ getting \ a \ white \ ball \boxed{\boxed{\bold{\frac{4}{20} = \frac{1}{5} }}}}$

$(ii)\bold{ Probability \ of \ not \ getting \ black} = 1-\dfrac{7}{20} = \boxed{\boxed{\bold{\dfrac{13}{20}}}}$

$(iii) \bold{ Probability \ of \ getting \ neither \ white \ or \ black} = \boxed{\boxed{\bold{\dfrac{9}{20}}}}$