A bag has seven red, four white and three green balls while another bag has five red,six yellow and three blue balls. A bag is selected at random and a ball drawn out of it,then find the probability that the ball drawn is red
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Answer:
Total no. Of balls in first bag = 14
7 - red
4 - white
3 - green
Total no. Of balls in second bag = 14
5 - red
6 - yellow
3 - blue
As, P(E) =Favourable no. /Total no.
Therefore, P of red balls in bag =
No. Of balls un first bag + no of balls in second bag/total no. Of balls in both the bag.
P[E] = 7+5/28
=12/28
=3/7
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