Math, asked by Saiqa, 1 year ago

a bag of marbles contain 6 red and 4 blue .if 3 marbles are drawn at random what is probability contain exactly 2 red and 1 blue

Answers

Answered by niral
0

Answer:

Step-by-step explanation:

→ Part 1: Let's find out the probability of 3 scenarios. In the first, the order is Order1; in the second scenario, the order is Order2; in the third scenario, the order is Order 3. We do not care whether all orders are same/different.

→ Part 2: We would find probabilities of each order.

→ Part 3: We add up the individual probabilities, as those events are mutually exclusive.

→ Now, in our case,

→ Part 1:

First select which order you want. There are 3 orders: BRR, RBR, RRB.

→ Part 2:

Find the probability of each event. This is what is done in some comments. That probability is 1/6. From the point of view of our approach, it is only happenstance that the probabilities come out to be the same.

→ Part 3:

Since there are 3 mutually exclusive ways to get the final scenario, we need to add the three individual event probabilities.

→ Final probability = 1/6 +1/6 + 1/6 = 1/2. This is what is done in a couple of answers at the end.


niral: mark me as brainliest answer.
Saiqa: But in my options there is ans is 1/3
Saiqa: Plzzz tell me it's ans
niral: then you take 1/3.
Answered by praveen6152
0

Answer:

no of red marbles - 6

no of blue marbles - 4

probabillity of marbles which are red

2/6 - 1/3- 3.3

probability of marbles which are blue - 1/3


Saiqa: Yup correct ans but 3.3 come from where?
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