a bag of marbles contain 6 red and 4 blue .if 3 marbles are drawn at random what is probability contain exactly 2 red and 1 blue
Answers
Answer:
Step-by-step explanation:
→ Part 1: Let's find out the probability of 3 scenarios. In the first, the order is Order1; in the second scenario, the order is Order2; in the third scenario, the order is Order 3. We do not care whether all orders are same/different.
→ Part 2: We would find probabilities of each order.
→ Part 3: We add up the individual probabilities, as those events are mutually exclusive.
→ Now, in our case,
→ Part 1:
First select which order you want. There are 3 orders: BRR, RBR, RRB.
→ Part 2:
Find the probability of each event. This is what is done in some comments. That probability is 1/6. From the point of view of our approach, it is only happenstance that the probabilities come out to be the same.
→ Part 3:
Since there are 3 mutually exclusive ways to get the final scenario, we need to add the three individual event probabilities.
→ Final probability = 1/6 +1/6 + 1/6 = 1/2. This is what is done in a couple of answers at the end.
Answer:
no of red marbles - 6
no of blue marbles - 4
probabillity of marbles which are red
2/6 - 1/3- 3.3
probability of marbles which are blue - 1/3