Question

A bag of wheat weighs 200 kg to what height should it be raised so that its ep is become 9800 j

Answer 1

Mass = 200 kg

height = h (say)

g = 9.8 m/s^2

now

PE = 9800 J

200 x h x 9.8 = 9800

h = ( 98 x10 )/ (98 x 2)

h = 5 m

Answer 2

$\huge\star\sf\underline\pink{Solution :-}$

$\sf{We\:have,} \\ \\ \sf{Potential\: Energy (pe) = 9800\:j} \\ \\ \sf{Mass(m) = 200\:kg}$

$\sf{Acceleration\:due \:to\: gravity (g) = 9.8\:ms^{-2} } \\ \\ \sf\underline\red{Height =?} \: \: \: \sf\purple{(To\:be\: calculated)}$

$\sf{Now,} \\ \\ \sf{Formula :-} \\ \\ \huge\underline\green{\boxed{\sf{P.E. = m \times g \times h}}} \\ \\ \sf{We\:get,} \\ \\ \implies\sf{9800 = 200 \times 9.8 \times h}$

$\sf{So,} \\ \\ {\sf{ h = \dfrac{ \cancel{9800}}{ \cancel{200} \times 9.8} }}$

$\implies\huge\underline\pink{\boxed{\sf{h = 5m}}} \\ \\ \sf{ Thus,} \\ \\ \sf{The\:bag\:be\:raised\:to\:a\: height\:of\:5\: metres.}$