A bag of wheat weighs 200kg. To what height should it be raised so that it's potential energy may be 9800 joules? (g=9.8m/s↑2) (5m)
Answers
Answered by
167
Mass = 200 kg
height = h (say)
g = 9.8 m/s^2
now
PE = 9800 J
200 x h x 9.8 = 9800
h = ( 98 x10 )/ (98 x 2)
h = 5 m
height = h (say)
g = 9.8 m/s^2
now
PE = 9800 J
200 x h x 9.8 = 9800
h = ( 98 x10 )/ (98 x 2)
h = 5 m
maria9:
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Answered by
173
Answer:
Explanation:
Given :-
Mass of the bag = 200 kg
Potential energy = 9800 J
Gravity = 9.8 m/s²
To Find :-
Height = ??
Formula to be used :-
Potential energy = mgh
Solution :-
Potential energy = mgh
9800 = 200 x h x 9.8
h = 9800 / 200 x 9.8
h = 5 m
Hence, the height should it be raised 5 m.
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