Question

A bag of wheat weighs 200kg to what height should it be raised sothat its pe may be 9800joule

Answer 1

PE.= mgh,
m=200kg
g=9.8m/s²
PE=9800 J
so, h= (mg)/PE
=( 200×9.8)/9800
=0.2 m

Answer 2

Answer:

$\bf\underline{\underline{solution}}$

1) take g as 10m/s

potential energy = 9800 joules

weight = 200kg

$PE = mass × g × height \\ 9800 = 200 \times 10 \times h \\ h = \frac{9800}{200 \times 10} \\ h = 9.8m$

∴ the height is 9.8 metres

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2) take g as 9.8m/s

potential energy = 9800 joules

weight = 200kg

$PE = mass × g × height \\ 9800 = 200 \times 9.8 \times h \\ h = \frac{9800}{200 \times 9.8} \\ h = 10m$

∴ the height is 10meters

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all done :D