Question

A bags contains 20 bulbs out of which 6 bulbs are defective if one bulb is drawn at random y find the probility that drawn bulb is non defective

Answer 1

Answer:

7/10

Step-by-step explanation:

Bulbs which are not defective are

20-6=14

so probability is

14/20=7/10

Answer 2

Total no.of bulbs = 20

Bulbs which are non defective = 14 [20-6]

we know that,

$probability = \frac{no.ofoutcomes}{total \: outcomes}$

so , probability of non defective bulbs ,

$probabilty = \frac{14}{20} = \frac{7}{10}$

Therefore , probability = 7/10