Question

A baker has 235 plain bis and 282 creamy bis. He wants to stack them in such a way that each stack had the same n.o and same type of bis and they take up the least area of the tray .what is the n.o of bis that can be placed in each stack for this purpose

Answer 1

Answer:

Step-by-step explanation:

444 = 2*2*3*37

276 = 2*2*3*23

LCM of (444 and 276) = 2*2*3 = 12

thus, the no. of biscuits that can be placed in each stack for this purpose = 12

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Answer 2

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⬇️HERE IS YOUR ANSWER⬇️

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FACTORS OF 235 AND 282

235 = 5×47

282 =2×3×47

HCF = 47
thus, no. of biscuits that can be placed = 47

HOPE THIS ANSWER HELPS YOU

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