Math, asked by sanakhan9795166sp, 1 year ago

The dimensions of a room are 8m×6m×h.it has two doors each of 2m×1m and 1 almirah of size 3m×2m.the cost of covering the walls by wallpaper which is 40cm wide at rupees 1.25 per m is rs.362.50.find hight.

Answers

Answered by jarpana2003
37

Answer:

Step-by-step explanation:

Area of four walls ka formula lagakar area nikla 28hm2

Area of both the doors and almirah is 10m2

Area to be painted=28h-10

Painted area= 362.50/1.25=290

Now

290*0.40=116

According to the question

116=28h-10

126=28h

h=126/28

h=4.5

hence the height is 4.5m


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Answered by aman9876abc
21

Area of wall=2(l+b)h

=2 *14*h

=28h

Area of 2 door=2*2*1

=4m^2

Area of almary=6m^2

total area of wallpap.=28h -4-6/40=362.5/1.25

H=4.5m

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