A bakery is selling cakes at $4 each. By setting up an inequality, find the maximum
number of cakes that can be bought with $39.
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4
✪||Solution||✪
price of each cake = $4
no. of cake in $39 = $39 ÷ 4
= 9.75 cakes
= 9 cakes
9 cakes were bought in $39.
Answered by
1
Given ,
- Price of Cake = $4 per cake
- Aviable money = $39
So , the maximum no. of cakes that can buy with $39 is ,
- Total money ÷ Price of one cake
- = 39 ÷ 4
- = 9.75
- Or 9 cakes.
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