Question

From 2.8 L of CO2 gas NTP , 1.5 x 10²² molecules are removed. Determine remaining mass of CO2 ??​

Answer 1

Answer:

the remaining weight of CO2 is 4.4 g

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Explanation:

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Answer 2

Answer:

We know that 6.022 X 1023 molecules = 1 mol

1 molecule = 1/6.022 × 1023 moles

1023 molecules = 1023/ 6.022 × 1023 = 1/6.022 mol

Number of moles = given mass / molar mass

given mass of CO2 = no. of moles X molar mass

= 1 X 44 g/mol

6.022

= 0.73 g

Hence, 1023 molecule of CO2 weighs 0.73 g.