Question

a) Balance the following chemical equations.
1) Zn + HCI —>ZnCl2 + H2
ii) N2O5 H2O —> HNO3
1) H2O2—>H2O +O2
iv) Pb +O2 –> PBO​

Answer 1

$\mathcal{1st~equation-}$

[tex]\large\sf{The~ skeletal ~equation ~is -}[/tex]

$\sf{Zn + HCl → ZnCl2 + H2}$

$\bold{Step~1:}$

Count the number of times an element is occurring on both LHS and RHS in this equation.

Component      Reactant       Product

Zinc                       1                     1

Chlorine                1                     2

Hydrogen               1                    2

$\sf{This~ is ~an ~unbalanced~ equation.}$

$\bold{Step~2:}$

Let’s balance the equation by multiplying HCl on the reactant side by 2.

The balanced equation is  

[tex]\sf{Zn + 2HCl⇒ZnCl2 + H2 }[/tex]

∴ Number of atoms of each element of reactants = Number of atoms of each element of products.

$\mathcal{2nd~equation}$

Reactant                    Products

N⇒2                           N⇒1 × 2 = 2

O⇒5+1=6                      O⇒6

H⇒2                              H⇒1

∴ N2O5 + H2O = HNO3 Balanced Equation,

$\mathcal{3rd~equation}$

$\sf{Hydrogen~Peroxide = Water + Dioxygen}$

Reactants                       Products

Hydrogen Peroxide       Water - H₂O

⇒ H₂O₂                          Dioxygen - O₂

                                             

∴ The Balanced equation is

$\sf{2H₂O₂ ⇒ 2H₂O + O₂}$

$\mathcal{4th~equation}$

Balanced Equation ⇒ Lead + Dioxygen = Lead(II) Oxide

Reactants             Products

Lead - Pb            Water - H₂O

Dioxygen - O₂    Lead(II) Oxide - PbO

Hope it helps!!

Brainliest pls.....