A ball comes down with gravity at an altitude of 10 meters with initial velocity. If it collides with the ground, it gives 50% energy in the collision and then returns to the same height, so tell the initial velocity.
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Explanation:
HEY MATE ..
Initial total energy at height h is, = 1/2 mu ^2 + mgh
⇒Energy of ball after collision, =50% of total energy.
⇒As ball rebounds to same height h, then
mgh= 50% 0f total energy.
⇒1 /4 mu ^2 + 1 / 2 magh .
⇒
therefore, u =
sqrt(2gh)=14m/s
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