Question

a ball drop from the top of a tower having height 20m and reaches ground in 10s. find its velocity when it reaches the ground.​

Answer 1

Answer:

s=h=20

a=g=±10m/s=10m/s (since it is dropped)

v^2-u^2= 2as

v^2=2x10x20 (u=0; it is dropped not thrown)

v=20m/s

for calculating time

we know,

v=u+at

20= 0+ 10xt

t=2seconds

thus, it will attain a speed of 20m/s before touching the ground, but the time taken to reach the ground is 2seconds. Because the velocity is not uniform but acceleration/gravity is. If still there is any confusion. Try the same problem with 80 of height.

Explanation:

Answer 2

Answer:

heloooo

Explanation:

same as above mate ✌️