Physics, asked by ashokkumar76, 9 months ago

A ball droped from top of the building reached the ground in 3 second. calculate. 1. The height of the building .
please answer the question urgently please
class 9th ​

Answers

Answered by laxmi1783
1

Answer:

Assume that the acceleration downwards = gravitational field strength = 9.8 (2 s.f)

Assume that the mass of the ball is negligible and there is no air resistance.

Use the equation s=ut+1/2at2

s=height of building

t= time taken for the ball to drop

u=initial velocity ; this = 0, because when the ball is dropped it has no speed initially, however if the question had said projected instead of dropped then it must have an initial speed. In this scenario we assume it has 0 initial speed since the question says dropped.

Substitute values to equation :

s=(0*3)+(1/2*9.8*3^2)

s=(1/2*9.8*3^2)

s=44.1m

Explanation:

Answered by AdhyanJain
1

Answer:

Assume that the acceleration downwards = gravitational field strength = 9.8 (2 s.f)

Assume that the mass of the ball is negligible and there is no air resistance.

Use the equation s=ut+1/2at2

s=height of building

t= time taken for the ball to drop

u=initial velocity ; this = 0, because when the ball is dropped it has no speed initially, however if the question had said projected instead of dropped then it must have an initial speed. In this scenario we assume it has 0 initial speed since the question says dropped.

Substitute values to equation :

s=(0*3)+(1/2*9.8*3^2)

s=(1/2*9.8*3^2)

s=44.1m

Read more on Brainly.in - https://brainly.in/question/17284053#readmore

Explanation:

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