Question

A ball dropped from the top of a building passes past a window of height h and time t if it's spped at the top and the bottom edges of the window are denoted by V1 and V2 respectively which of the following set of equations are correct ​

Answer 1

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$\huge\fcolorbox{red}{yellow}{Question}$

A ball dropped from the top of a building passes past a window of height h and time t if it's spped at the top and the bottom edges of the window are denoted by V1 and V2 respectively which of the following set of equations are correct

$\huge\purple{\boxed{\boxed{Answer }}}$

A ball is dropped from the top of the building .

A ball is dropped from the top of the building .The ball takes 0.5 seconds to fall past the 3 m height of a window some distance from the top of the building

If the speed of the ball at the top and at the bottom of the window are VT and VB

$speed \: of \: the \: ball \: at \: te \: top \: of \: the \: widow = v_{t}$

$sped \: of \: the \: ball \: at \: the \: bottom \: of \: the \: window = v_{b}$

$using \: motion \: equation$

${v}^{2} - {u}^{2} = 2gs$

$v = u + gt$

$where \: v \: = v_{b}$

$u \: = v_{t}$

$g \: = \frac{9.8m}{ {s}^{2} }$

$s = 3m$

$t = 0.5sec$

substitute all these values in the formula

$v \binom{2}{b } - v \binom{2}{t } = 2(9.8)(3) = 58.8$

$( v_{b} + v_{t}) ( v_{b} - v_{t}) = 58.8 - - - - eq1.$

$v_{b} = v_{t} + (9.8)(0.3)$

$v_{b} - v_{t} = 2.94 - - - - - eq2.$

$v_{b} + v_{t} = \frac{58.8}{2.94}$

$v_{t} + v_{b} = 20$

$hence \: the \: value \: of \: v_{t} + v_{b} = 20 \frac{m}{s}$

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