Question

A ball drroped from a height from 20 m and it accerlates with acceralation 10 m!/s2 with what velocity strike the ground how much time it strike​

Answer 1

Answer:

10s²

Explanation:

Velocity=20÷10

=10s²

Answer 2

Answer:

v=2√10

Explanation:

given data:

s=20 m (s is distance)

a=10 m/s^2

u=0 m/s (becouse ball was at rest before dropped)

we know that,

v^2=u^2+2as

=O+2×10×20

=20×20

v^2=40

v=√40

v=√4×10

v=2√10 m/s

so the ball strikes the ground with 2√10 m/s velocity.

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