A ball fall off a table and reaches the ground in 1 s . Assuming g=10 m/s^2 calculate its speed on reaching the ground and the height of the table
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u=0
g=10m/s²
t=1sec
s=ut+1/2gt²
s=0(1)+1/2*10*1*1
s=5m
so table height 5m
v=u+gt
v=0+10*1
v=10m/s
so the velocity at reaching the ground would be 10m/s
plz mark as brainlist answer
g=10m/s²
t=1sec
s=ut+1/2gt²
s=0(1)+1/2*10*1*1
s=5m
so table height 5m
v=u+gt
v=0+10*1
v=10m/s
so the velocity at reaching the ground would be 10m/s
plz mark as brainlist answer
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