Question

A ball falling in a lake of depth 200 m shows 0.1%
decrease in its volume at the bottom. What is the
bulk modulus of the material of the ball :
(1) 19.6 x 108 N/m2 (2) 19.6 x 10-10 N/m²
(3) 19.6 x 1010 N/m2 (4) 19.6 x 10-8 N/m²​

Answer 1

≡QUESTION≡

A ball falling in a lake of depth 200 m shows 0.1%  decrease in its volume at the bottom. What is the  bulk modulus of the material of the ball :

(1) 19.6 x 108 N/m²

(2) 19.6 x 10-10 N/m²

(3) 19.6 x 1010 N/m²

(4) 19.6 x 10-8 N/m²

                                                       

║⊕ANSWER⊕║

Formula to be used:

K = PV/ ΔV

= hdg / ΔV

= 200 * 10³ * 9.8 / 0.001

= 19.6 * 10⁸ N/m²

∴ Option A is the answer

                                                       

Answer 2

Question

▪ A ball falling in a lake of depth 200 m shows 0.1%decrease in its volume at the bottom. What is thebulk modulus of the material of the ball ?

(1) (1) 19.6 x 108 N/m2

(2) 19.6 x 10-10 N/m²

(3) 19.6 x 1010 N/m2

(4) 19.6 x 10-8 N/m²

solution:-

▪ By using the this is Formula▪

➝ K= PV/∆V

➝ hdg/∆V

➝ 200×10^3×9800/1

➝ 19.6×10^8 n/m^2

Hence option (a) is the correct answer.

...... Hope this answer helps you..

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