A ball falling in a lake of depth 200m shows a decrease of o.1% in its volume at the bottom. The bulk modulus of the ball is
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Hey dear,
◆ Answer-
B = 19.6×10^8
◆ Explaination-
# Given-
h = 200 m
∆V/V = 0.1 %
# Solution-
Bulk modulus of material is given by-
Bulk modulus = Pressure / Strain
B = P / (∆V/V)
Here, we know
P = ρgh
∆V/V = 0.1 %
B = ρgh / (∆V/V)
B = 1000×9.8×200 / (0.1/100)
B = 19.6×10^8
Bulk modulus of the ball material is 19.6×10^8.
Hope this helps...
◆ Answer-
B = 19.6×10^8
◆ Explaination-
# Given-
h = 200 m
∆V/V = 0.1 %
# Solution-
Bulk modulus of material is given by-
Bulk modulus = Pressure / Strain
B = P / (∆V/V)
Here, we know
P = ρgh
∆V/V = 0.1 %
B = ρgh / (∆V/V)
B = 1000×9.8×200 / (0.1/100)
B = 19.6×10^8
Bulk modulus of the ball material is 19.6×10^8.
Hope this helps...
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