Question

a ball falls off a table and reachesthe ground in 1s .assuming g=10 m/s ,calculate its speed on reaching the ground and the height of the table

Answer 1

hii
In this case the initial velocity is always zero so
u=0
t=1 sec
g=10m/sec2
v=?

v=u+at
v=0+10*1
v=10m/sec

$s = ut + (1\div2)a {t}^{2}$
$s = 0 \times 1 + (1 \div 2)10 \times 1^{2} \\ s = 0 + (1 \div2 ) \: 10 \\ s = 0.5 \times 10 \\ s = 5m$
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