A ball falls off table and reaches the ground in 1 s. Assuming g=10 m/s , calculate its speed on reaching the ground and the height of the table
Answers
Answered by
1
v=u+gt
v=0+10*1
v=10m/s
hope this helps you out.
Answered by
9
Answer:
Speed on reaching the ground=10m/s
Height of the table=5m
Explanation:
Given,
u=0m/s
a=g=10m/s^2
t=1sec
So by using 1st eq of motion, we get,
v=u+at
v=0+10*1
v=10m/s
Now, by using 2nd eq of motion, we get,
s=ut+1/2at^2
s=0*1+1/2*10*1^2
s=5m
Pratham4849:
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