Question

A ball falls off table and reaches the ground in 1 s. Assuming g=10 m/s , calculate its speed on reaching the ground and the height of the table​

Answer 1

v=u+gt

v=0+10*1

v=10m/s

hope this helps you out.

Answer 2

Answer:

Speed on reaching the ground=10m/s

Height of the table=5m

Explanation:

Given,

u=0m/s

a=g=10m/s^2

t=1sec

So by using 1st eq of motion, we get,

v=u+at

v=0+10*1

v=10m/s

Now, by using 2nd eq of motion, we get,

s=ut+1/2at^2

s=0*1+1/2*10*1^2

s=5m