Question

a body moving with uniform acceleration has a velocity of-11cm/s when its x coordinate is 3.00cm. if its x coordinate 2s later is -5cm, what is the magnitude in cm/s^2 of its acceleration ​

Answer 1

total distance covered (s)= 8 cm

velocity (u)= -11 cm/s

s= ut+ 0.5 ft^2

8=-11×2+0.5×f×4

f =15 cm/s^2