A ball hits a wall horizontally at 6.0m per second .it rebound horizontally at 4.4m per second the ball is in the contact with the wall for 0.040s what is the acceleration of the ball
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HEYA FRIEND HERE IS THE ANSWER
Initial velocity = 6 m/s ( forward)
final velocity = 4.4 m/s ( backward) = -4.4 m/s ( forward )
acceleration = change in velocity/time
= ( -4.4 -6)/ 0.04 = -10.4/0.04
= -1040/4 = -260 m/s² ( forward )
hope it helps to you.
Initial velocity = 6 m/s ( forward)
final velocity = 4.4 m/s ( backward) = -4.4 m/s ( forward )
acceleration = change in velocity/time
= ( -4.4 -6)/ 0.04 = -10.4/0.04
= -1040/4 = -260 m/s² ( forward )
hope it helps to you.
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