a ball hits a wall horizontally with a velocity of 6m/sec . after hitting wall it rebounds horizontally with a velocity of 4.4 m/sec.if the ball remains in the contact of all for 0.040 sec. the acceleration of ball would be ??
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1
Answer:
Acceleration (a)=
t
(v−u)
=
0.040
6−(−4.4)
=
0.040
10.4
=260m/s
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Answered by
1
Answer:
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