Question

a ball hits a wall horizontally with a velocity of 6m/sec . after hitting wall it rebounds horizontally with a velocity of 4.4 m/sec.if the ball remains in the contact of all for 0.040 sec. the acceleration of ball would be ??​

Answer 1

Answer:

Acceleration (a)=

t

(v−u)

=

0.040

6−(−4.4)

=

0.040

10.4

=260m/s

2

Answer 2

Answer:

this is the answer

I hope it is helpful to you

Explanation:

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