Question

a ball initially at rest is dropped from a height hour state the ratio of the distance covered by it in the first and the third second of its fall

Answer 1

Explanation:

S=ut+21at2

u=0

H=21gt2

Now H for first second will be

H=21g(1)

H for second second will be

H=21g(4)

H for third second will be

H=21g(9)

Now as we have to Know the distance of second second we need to substract the distance of first second.

So required H1=g21

H2=g24−g21=g23

H3=g29−g24=g25

Put the values of H inW=mgH

On dividing above 3eqs we get :  1:3:5

So required ratio is 1:3:5