Question

If q(x)=x^2-2✓2 x +1, find q (2✓2)​

Answer 1

Answer:

1

Step-by-step explanation:

p(x)=x²-2√2x+1.

p(2√2)=(2√2)²-(2√2*2√2)+1

p(2√2)=(2√2)²- (2√2)²+1

=0+1.

=1.

Therefore, the answer is 1.

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Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow q(x)= x^2-2 \sqrt{2}x+1$

$\sf\dashrightarrow x=2\sqrt{2}$

$\large\underline\bold{SOLUTION,}$

PUTTING THE VALUE OF X IN THE GIVEN EQUATION,

$\sf\implies x^2-2 \sqrt{2}x+1$

$\sf\implies (2\sqrt{2})^2-2 \sqrt{2} (2\sqrt{2})+1$

$\sf\implies 4(2)-4(2)+1$

$\sf\implies \cancel{4(2)-4(2)}+1$

$\sf\implies 1$

$\large{\boxed{\bf{ \star\:\: \implies \:1 \:\: \star}}}$

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