A ball is drop from a height of 10 m , if the energy of the ball is the reduced by 40 % after striking the ground , how much high can the ball bounce back?
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Before the ball falls it has a potential energy of 10 x M x g newtons wher M is the mass of the ball in kg. At the point of impact this has been converted to kinetic energy, and 40% is lost on impact . The ball will rise to the point where it has 60% of the potential energy it started with - 6metres, following the Law of Conservation of Energy.
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Answer:
Total energy of the ball = m g h
=mg10
=100m kgm
2
s
−2
Energy with which it moves up the ground after striking= 60% of the total energy
E=
100
60
×100m kgm
2
s
−2
Height to which the ball will bounce back
h=
m×g
E
=6 meter
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