Question

A ball is dropped from 4 meters above the ground if it begins at rest how long does it take to hit the ground accerelation due1 to gravity is 9.81

Answer 1

Answer:

Explanation:s=ut+1/2gt^2

Therefor,here s=4,u=o,g=9.8

So, 4=1/2*9.8*t^2

t^2=8/9.8

t=0.9sec

Answer 2

The time taken by it to hit the ground is 0.903 seconds.

Explanation:

It is given that, a ball is dropped from 4 meters above the ground if it begins at rest. We need to find the time taken by it to hit the ground. The ball will dropped under the action of gravity.

The second equation of motion is given by :

$h=ut+\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}}\\\\t=\sqrt{\dfrac{2\times 4}{9.81}}\\\\t=0.903\ s$

So, the time taken by it to hit the ground is 0.903 seconds.

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Kinematics

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